-16x^2+9x+112=0

Solution for -16x^2+9x+112=0 equation:

-16x^2+9x+112=0

a = -16; b = 9; c = +112;
Δ = b2-4ac
Δ = 92-4·(-16)·112
Δ = 7249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{7249}}{2*-16}=\frac{-9-\sqrt{7249}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{7249}}{2*-16}=\frac{-9+\sqrt{7249}}{-32}
$